Friday 11 March 2011

The beginning of eternity

Answer to yesterday's riddle: We could solve for distance directly, and come up with the summation of an infinite series. But since we're given the bee's speed, all we need is to solve for the time that the bee is in flight, since Distance=Speed * Time. To find the speed, we look at the trains: They are 180 km apart, travelling toward each other at 270 km/h (150 + 120) relative to a stationary observer. This means it takes them 2/3 of an hour, or 40 minutes, to collide. At 300 km/h over 40 minutes, the bee travels exactly 200 km.

P.S.: The B-Line is the name of one of the bus routes in Vancouver!
Takes a bit of computation... But once you get over that, it's simple no? Our next riddle is a challenge from Grafted:

I am the beginning of eternity, the end of time and space, the beginning of every end, and the end of every place. What am I?

21 comments:

  1. I've solved this one before, before it was told to me, but I don't want to ruin it for everyone else.

    Hint: Pay attention to the structure of the words mentioned in the riddle.

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  2. Oh man, this one stumped me. >.<

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  3. The Letter E!!!
    Thanks to my boyfriend. He just guessed that as I read it to him, and if you ask me it is genius.

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  4. No idea. At first I thought of that alpha and omega line from the bible, but nope.

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  5. google told me its the letter e :D

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  6. I am a needle in some dopeheads arm on Hastings street!

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  7. So yes, time travels, but does it not change? I submit that we live in a universe that dictates no B would mindlessly fly back and forth, no matter how small or mindless. Thus, every calculation to the B's route must be made. It would look like this,

    (x*40minutes)=<(x*40minutes)^infinity>

    Where x would represent the measure of an infinitesimally small number that sequences the moments in which time can change. I think you'll notice that the results, ie. probability of this is far greater than infinity^2, which is exactly what I'm talking about! :D

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